vba跳转

```vb

Private Sub btnJump_Click()

Dim jumpTarget As String

jumpTarget = txtJumpTo.Text ' Assuming txtJumpTo is a TextBox control containing the target location

' Validate the jump target

If jumpTarget = "" Then

MsgBox "Please enter a valid jump target"

Exit Sub

End If

' Perform the jump

Select Case jumpTarget

Case "Page1"

' Code to jump to Page1

' Me.Page1.Visible = True

' Me.Page2.Visible = False

' ...

Case "Page2"

' Code to jump to Page2

' Me.Page1.Visible = False

' Me.Page2.Visible = True

' ...

Case Else

MsgBox "Invalid jump target"

End Select

End Sub

```

以上是一个简单的VB代码段，用于在用户点击按钮时根据输入跳转到特定位置或页面。在实际应用中，您需要根据具体的跳转逻辑和页面结构进行调整。